Sabtu, 29 September 2012

PHP (Latihan 2)

Posted by Unknown On Sabtu, September 29, 2012 | No comments
Gambar 1.0
Ketika Button Simpan Diclick Maka Akan Tampil Seperti Gambar 2.0

Gambar 2.0
Ketika Click Back Maka Akan Tampil Seperti Gambar 1.0

Coding/Listing Gambar 1.0 (Simpan Dengan Nama latihan2.html) :


<!doctype html public "-//W3C//DTD HTML 4.0 //EN">
<html>
<head>
       <title>Database TXT</title>
</head>
<body bgcolor="Gray">
<form action="simpan.php" method="post">
<h1 align="center">..:: Daftar Gaji Pegawai::..</h1>
<div align="center">
<table boder="3">
<tr>
    <td width="92">Nama Pegawai</td>
    <td width="3">:</td>
    <td width="271"><input type="text" name="nama"</td>
</tr>
<tr>
    <td>Nip Pegawai</td>
    <td>&nbsp;</td>
    <td><label>
    <input type="text" name="nip">
    </label></td>
</tr>
<tr>
    <td>Kode Jabatan</td>
    <td>:</td>
    <td><input type="radio" name="kode" value="Staff">Staff
    <input type="radio" name="kode" value="Manager">Manager
    <input type="radio" name="kode" value="Direktur">Direktur
    </td>
</tr>
<tr>
    <td colspan="3"><input type="submit" value="Simpan">
        <input type="reset" value="Hapus"></td>
</tr>
</table>
</form>
</body>
</html>


Coding/Listing Gambar 2.0 (Simpan Dengan Nama simpan.php) :


<!doctype html public "-//W3C//DTD HTML 4.0 //EN">
<html>
<head>
       <title>Database TXT</title>
</head>
<body bgcolor="gray">
<?
$nama=$HTTP_POST_VARS['nama'];
$nip=$HTTP_POST_VARS['nip'];

if($kode=="Staff"){
            $gaji=1200000;
    }elseif($kode=="Manager"){
            $gaji=2000000;
    }else{
            $gaji=5000000;}

echo "<h1>Data Karyawan</h1>";
echo "<pre>";
echo "<strong>";
echo "<font size=3>";
echo "Nama Saya      : $nama<br>";
echo "Nip Saya       : $nip<br>";
echo "Jabatan        : $kode<br>";
echo "Gaji           : $gaji<br></strong></font>";
 ?>
<br>
<center>
<h3><a href="latihan2.html">Back</a></h3>
</center>
</body>
</html>

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